0=-0.11x^2+7

Solution for 0=-0.11x^2+7 equation:

0=-0.11x^2+7

We move all terms to the left:

0-(-0.11x^2+7)=0

We add all the numbers together, and all the variables

-(-0.11x^2+7)=0

We get rid of parentheses

0.11x^2-7=0

a = 0.11; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·0.11·(-7)
Δ = 3.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.08}}{2*0.11}=\frac{0-\sqrt{3.08}}{0.22}
=-\frac{\sqrt{}}{0.22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.08}}{2*0.11}=\frac{0+\sqrt{3.08}}{0.22}
=\frac{\sqrt{}}{0.22}
$